#include<stdio.h>
int main()
{
 int i;
 for(i=0;;i++)
if(((i*8+7)*8+1)*8+1==(34*i+15)*17+4)
{
    printf("The required number is :%d\n",(34*i+15)*17+4);
    break;
}


}
//吴昌源

